wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of nC0+nC1+...........+nCn


A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C


Consider the binomial expansion of (1+x)n

(1+x)n= nC0 nC1..........nCn

Put x = 1

nC0+nC1+nC2...........+nCn

nC0+nC1+nC2...........+nCn = 2n


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Product of Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon