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Question

Find the value of nC0+nC1+...........+nCn


A

0

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B

1

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C

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D

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Solution

The correct option is C


Consider the binomial expansion of (1+x)n

(1+x)n= nC0 nC1..........nCn

Put x = 1

nC0+nC1+nC2...........+nCn

nC0+nC1+nC2...........+nCn = 2n


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