Find the value of $n$ , if the median of the numbers $n + 3, n + 7, . . . . n + 31, n + 35$ is $30$ .

Open in App

Solution

The numbers are $n + 3, n + 7, . . . . n + 31, n + 35$
$n + (4 (1) - 1), n + (4 (2) - 1), . . . ., n + (4 (8) - 1), n + (4 (9) - 1)$
Median is $n + (4 (\frac{1 + 9}{2}) - 1) = n + 19 = 30$
$⟹ n = 11$

Suggest Corrections

Similar questions

If $^{35} C_{n + 7} =^{35} C_{4 n - 2}$ , then write the values of n.

{I f}^{35} C_{n + 7} =^{35} C_{4 n - 2},

n

m \in N

m = \frac{n^{2} - n - 35}{n - 4}

\sqrt{7}

\sqrt{3}

\sqrt{7}

\sqrt{3}

(a + b)^{n^{2} + 3}

7

n, (n \in N)

Join BYJU'S Learning Program