Find the value of - n- in the following- 7 2n-1 - 49- 7 3

We know that, ∵a^ma^n=a^m n so, 7^2n+17^2=7^2n+1 2 =7^2n 1 now, 7^2n 1=7^3 As bases are equalpowers are equal 2n 1=3 n=2 ...

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Exponential Representation for Irrational Numbers

Find the valu...

Question

Find the value of ' $n$ ' in the following:
$7^{2 n + 1} \div 49 = 7^{3}$

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7^{2 n + 1} \div 49 = 7^{3}

{(\frac{2}{3})}^{3} \times {(\frac{2}{3})}^{5} = {(\frac{2}{3})}^{n - 2}

(- 3)^{n + 1} \times (- 3)^{5} = (- 3)^{- 4}

7^{2 n + 1} \div 49 = 7^{3}

5^{2 n} \times 5^{3} = 5^{11}

9 \times 3^{n} = 3^{7}

8 \times 2^{n + 2} = 32

7^{2 n + 1} \div 49 = 7^{3}

{(\frac{3}{2})}^{4} \times {(\frac{3}{2})}^{5} = {(\frac{3}{2})}^{2 n + 1}

{(\frac{2}{3})}^{10} + {\{{(\frac{3}{2})}^{2}\}}^{5} = {(\frac{2}{5})}^{2 n - 2}

\forall n \in N, 7^{2 n} - 48 n - 1

|\begin{matrix} - 1 & 7 \\ 2 & 4 \end{matrix}|

|\begin{matrix} 5 & 3 \\ - 7 & 0 \end{matrix}|

|\begin{matrix} \frac{7}{3} & \frac{5}{3} \\ \frac{3}{2} & \frac{1}{2} \end{matrix}|

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