Find the value of $n$ in the following :
${(2^{2})}^{n} = {(2^{3})}^{4}$

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Solution

$\begin{matrix} {(2^{2})}^{n} = {(2^{3})}^{4} 2^{2 n} = 2^{12} S o, 2 n = 12 n = 6 \end{matrix}$

Thus value of n will be 6

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