Find the value of - -n- in the following- -3 n-1 - -3 5 - -3 -4

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Laws of Exponents for Real Numbers

Find the valu...

Question

Find the value of ' $- n$ ' in the following:
${(- 3)}^{n + 1} \times {(- 3)}^{5} = {(- 3)}^{- 4}$

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{(\frac{2}{3})}^{3} \times {(\frac{2}{3})}^{5} = {(\frac{2}{3})}^{n - 2}

(- 3)^{n + 1} \times (- 3)^{5} = (- 3)^{- 4}

7^{2 n + 1} \div 49 = 7^{3}

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\frac{2}{3} (4 n - 1) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}

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{(\frac{2}{3})}^{3} \times {(\frac{2}{3})}^{5} = {(\frac{2}{3})}^{n - 2}

(\frac{5}{3})^{2 n + 1} \times (\frac{5}{3})^{5} = (\frac{5}{3})^{n + 2} .

Find the value of n such that $\frac{2}{3} (4 n - 1) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}$ .

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