Question

Find the value of $n$ when:
$8\times 4^{n+2}=32$

Answer 1

$8\times 4^{n+2}=32$

$\Rightarrow 4^{n+2}=\frac{32}{8}$

$\Rightarrow 4^{n+2}=4^1$

By equating powers

$\Rightarrow n+2=1$

$\Rightarrow n=1-2=-1$