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Byju's Answer
Standard VII
Mathematics
Exponents with Unlike Bases and Same Exponent
Find the valu...
Question
Find the value of n when :
i)
5
2
n
×
5
3
=
5
9
ii)
8
×
2
n
+
2
=
32
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Solution
(1)
5
2
n
×
5
3
=
5
9
Apply law of exponents
x
a
×
x
b
=
x
a
+
b
5
2
n
+
3
=
5
9
⇒
2
n
+
3
=
9
2
n
=
9
−
3
2
n
=
6
n
=
3
(2)
8
×
2
n
+
2
=
32
2
3
×
2
n
+
2
=
2
5
Apply law of exponents
x
a
×
x
b
=
x
a
+
b
2
3
+
n
+
2
=
2
5
2
n
+
5
=
2
5
⇒
n
+
5
=
5
n
=
5
−
5
n
=
0
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0
Similar questions
Q.
Find the value of
n
when:
5
2
n
×
5
3
=
5
9
Q.
Find the value of n when:
(i) 5
2n
× 5
3
= 5
9
(ii) 8 × 2
n
+2
= 32
(iii) 6
2n
+1
÷ 36 = 6
3
Q.
Find the values of n in each of the following:
(i)
5
2
n
×
5
3
=
5
11
(ii)
9
×
3
n
=
3
7
(iii)
8
×
2
n
+
2
=
32
(iv)
7
2
n
+
1
÷
49
=
7
3
(v)
3
2
4
×
3
2
5
=
3
2
2
n
+
1
(vi)
2
3
10
+
3
2
2
5
=
2
5
2
n
-
2
Q.
Solve
1
)
156
2
n
×
5
3
=
5
9
, where
n
is the unit digit
2
)
8
×
2
×
n
2
=
32
Q.
Find the value of
n
when:
8
×
4
n
+
2
=
32
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Standard VII Mathematics
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