Find the value of n, Where n is an integer and 2^n-2 multiplied6^2n-4=1/(12^4 multiplied2)

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n

2^{n - 5} \times 6^{2 n - 4} = \frac{1}{12^{4} \times 2}

Question 73

Find the value of $n$ , where $n$ is an integer and $2^{n - 5} \times 6^{2 n - 4} = \frac{1}{12^{4} \times 2} .$

b = a + 1

b^{n} - (n - 1) a b^{n - 2} + \frac{(n - 2) (n - 3)}{⌊ 2} a^{2} b^{n - 4} - \frac{(n - 3) (n - 4) (n - 5)}{⌊ 3} a^{3} b^{n - 6} + . . . .

n

n (n + 1) = 6

2^{2 n} = 16

1 + i^{2} + i^{4} + i^{6} + . . . + i^{2 n}

i = \sqrt{- 1}, n \in N

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