wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of P(1) if the function P is defined as follows:
for x>0,P(x)=x5+x436x36
x<0,P(x)=x5+x4+36x36

A
-70
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
-36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
36
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
70
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A -70
We know x<0, then P(x)=x5+x4+36x36
P(1)=(1)5+(1)4+36(1)36
P(1)=1+13636
P(1)=272=70

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon