Find the value of $p (2), p (- 1)$ for the polynomial $p (x) = x^{3} - 5 x^{2} - 2 x + 24$

Open in App

Solution

$P (x) = x^{3} - 5 x^{2} - 2 x + 24$
$P (- 1) = (- 1)^{3} - 5 (- 1)^{2} - 2 (- 1) + 24$
$- 1 - 5 + 2 + 24 = 20$
$P (2) = (2)^{3} - 5 (2)^{2} - 2 (2) + 24$
$= 8 - 20 - 4 + 24$
= 8

Suggest Corrections

Similar questions

p (x) = x^{3} + 5 x^{2} - 2 x - 24

x = 2

P (x)

4

P (2) = - 1, P^{'} (2) = 0, P^{''} (2) = 2, P^{'''} (2) = - 12, P^{''''} (2) = 24

P^{^{''}} (1) =

P (2) = - 1

P^{'} (2) = 0

P^{''} (2) = 2

P^{'''} (2) = - 12

P^{i v} (2) = 24

P^{''} (1)

p (x) = x^{4} - {2 x}^{3} + {3 x}^{2} - p x + 3 p - 7

p (2) = 5

p (x) = x^{3} + 3 x^{2} + 2 x + t

(x - 1)

Join BYJU'S Learning Program