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Question

Find the value of P(2) where P(x)=4x37x2+4x+7

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Solution

Consider the given polynomial.
P(x)=4x37x2+4x+7

Put x=2, we get
P(2)=4(2)37(2)2+4(2)+7
P(2)=4(8)7(4)+8+7
P(2)=3228+8+7
P(2)=4728
P(2)=19

Hence, this is the answer.

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