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Question

Find the value of ‘p’ for the following distribution whose mean is 16.6.

x81215p202530
f121620241684

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Solution

Step 1: Find the value of fx

fx=x×f

x81215p202530
f121620241684f=100
fx8×12=9612×16=19215×20=30024×p=24p20×16=32025×8=20030×4=120fx=1228+24p

Step 2: Find the value of p.

Mean(x¯)=fxf16.6=1228+24p1001228+24p=16.6×1001228+24p=166024p=1660-122824p=432p=43224p=18

Hence, the value of p=18.


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