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Formation of a Quadratic Equation From It's Roots

Find the valu...

Question

Find the value of p, for which one root of the quadratic equation $p x^{2} - 14 x + 8 = 0$ is 6 times the other root.

p = 1

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p = 2

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p = 3

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p = 4

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Solution

The correct option is C p = 3
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Similar questions

p

p x^{2} - 14 x + 8 = 0

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{p x}^{2} - 14 x + 8 = 0 i s 6

p x^{2} - 14 x + 8 = 0

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p =

2 x^{2} + p x + 8 = 0

Find the value of ‘p’ for which the quadratic equations have equal roots.

(1)

(2)

(3)

(4)

(5)

(6)

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