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Question

Find the value of p for which the lines 2x+3y7=0 and 4ypx12=0 are perpendicular to each other.

A

4

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B

-4

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C

6

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D

-6

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Solution

The correct option is C

6


Given, 2x+3y7=0
3y=2x7
y=23x+73
Comparing with the slope intercept form of line y=m1x+c, we get,
Slope, m1=23

Now, 4ypx12=0 [Given]
4y=px+12
y=px4+124
Comparing with the slope intercept form of line y=m2x+c, we get,
Slope, m2=p4

Since both the lines are perpendicular to each other,
m1m2=1
23×p4=12p=12
p=6

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