Find the value of p if the lines, whose equations are 2x - y + 5 = 0 and px + 3y = 4 are perpendicular to each other.

Open in App

Solution

2x - y + 5 = 0

y = 2x + 5

Slope of this line = 2

px + 3y = 4

3y = -px + 4

y = $fraction numerator negative p over denominator 3 end fraction x plus 4 over 3$

Slope of this line = $fraction numerator negative p over denominator 3 end fraction$

Since, the lines are perpendicular to each other, the product of the slopes is -1.

$2 open parentheses fraction numerator negative p over denominator 3 end fraction close parentheses equals negative 1 fraction numerator 2 p over denominator 3 end fraction equals 1 p equals 3 over 2$

Suggest Corrections

Similar questions

2 x + 3 y - 7 = 0

4 y - p x - 12 = 0

Find the value of P for which the lines 2x + 3y -7 = 0 and 4y - px - 12 = 0 are perpendicular to each other.

If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.

(p + 1) x + y = 3

3 y - (p - 1) x = 4

p

p

8 p x + (2 - 3 p) y + 1 = 0

p x + 8 y - 7 = 0

Join BYJU'S Learning Program