Question

Find the value of $p$ in given equation, $\frac{p}{4}+\frac{p}{3}=55-\frac{p+40}{5}$.

Answer 1

Given, $\frac{p}{4}+\frac{p}{3}=55-\frac{p+40}{5}$

$\Rightarrow$ $\frac{3p+4p}{12}=\frac{275-p-40}{5}$ …[Taking LCM of the denominators]

$\Rightarrow$ $\frac{7p}{12}=\frac{235-p}{5}$ ...[On simplifying]

$\Rightarrow$ $5\left(7p\right)=12(235-p)$ …[Cross-multiplying the denominators]

$\Rightarrow$ $35p=2820-12p$

$\Rightarrow$ $47p=2820$

$\Rightarrow$ $p=60$.

Hence, the value of $p$ is $60$.