Find the value of p such that quadratic equation.
$(p - 12) x^{2} - 2 (p - 12) x + 2 = 0$ has equal roots.

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Solution

$\begin{matrix} I f r o o t s a r e e q u a l t h e n, D = 0 \Rightarrow 4 {(P - 12)}^{2} - 4 \times 2 (P - 12) = 0 \Rightarrow {(P - 12)}^{2} - 2 (P - 12) = 0 \Rightarrow (p - 12) {P - 12 - 2} = 0 \Rightarrow (P - 12) (P - 14) = 0 ∴ V a l u e o f P = 14 \end{matrix}$

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