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Question

Find the value of p(x)=4x2−3x+7 at x=1.

A
6
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B
7
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C
8
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D
9
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Solution

The correct option is C 8
Given polynomial is p(x)=4x23x+7
We need to find value of polynomial at x=1.
Then put the value of x=1 in the given polynomial, we get
p(x)=4(1)23(1)+7
p(x)=4×13×1+7
p(x)=43+7
p(x)=113=8
So, value of polynomial is 8.

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