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Factorisation by Common Factors

Find the valu...

Question

Find the value of $p (x)$ at $x = 1$ , given that $p (x) = 3 x^{2} + 5 x - 7$ .

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Solution

The correct option is A $1$
Given $p (x) = 3 x^{2} + 5 x - 7$ and $x = 1$
Put the value of $x = 1$ , we get
$p (1) = 3 (1)^{2} + 5 (1) - 7$
$\Rightarrow p (1) = 3 + 5 - 7$
$\Rightarrow p (1) = 1$
Therefore value of $p (x)$ at $x = 1$ is $1$ .

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