Find the value of $p (x) = x^{2} - 2 x + 5$ if $x = 2 {log}_{2}^{8}$

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Solution

$x = 2 l o g_{2} (2)^{3} = 6 P (x) = x^{2} - 2 x + 5 = 36 - 12 + 5 = 29$

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Find the value of p(x)=x2−2x+5 if x=2log82

x=2log2(2)3=6P(x)=x2−2x+5=36−12+5=29

Find the value of $p (x) = x^{2} - 2 x + 5$ if $x = 2 {log}_{2}^{8}$

$x = 2 l o g_{2} (2)^{3} = 6 P (x) = x^{2} - 2 x + 5 = 36 - 12 + 5 = 29$