Question

Find the value of polynomial $q\left(y\right)=2y^3-4y+\sqrt{11}$ at $y=1.(\sqrt{11}=3.32)$

• A. $1.32$
• B. $3$
• C. $2$
• D. $2.34$

Answer 1

The correct option is A $1.32$

Given, $q\left(y\right)=2y^2-4y+\sqrt{11}$

We need to find value of polynomial at $y=1$

Put the value $y=1$ in the given polynomial, we get

$q\left(y\right)=2(1{)}^2-4(1)+\sqrt{11}$

$\Rightarrow q\left(y\right)=2-4+\sqrt{11}$

$\Rightarrow q\left(y\right)=2-4+3.32$

$\Rightarrow q\left(y\right)=1.32$

Therefore, $q\left(y\right)=1.32$