Question

Find the value of polynomial $q\left(z\right)=5z^3-4z+\sqrt{2}$ at $z=2(\sqrt{2}=1.41)$

• A. $32.51$
• B. $33.41$
• C. $35.01$
• D. None

Answer 1

The correct option is B $33.41$

Given $q\left(z\right)=5z^3-4z+\sqrt{2}$ and $x=2$

On putting $z=2$, we get

$q\left(2\right)=5(2{)}^3-4(2)+\sqrt{2}$

$\Rightarrow q\left(2\right)=5\times 8-4\times 2+\sqrt{2}$

$\Rightarrow q\left(2\right)=40-8+1.41$

$\Rightarrow q\left(2\right)=33.41$