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Question

Find the value of 8P7,25P5,24C4,19C14.

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Solution

nPr=n!(nr)!

(1) 8P7=8!1!=8×7×6×5×4×3×2×1=40,320

(2) 25P5=25!20!=25×24×23×22×21=6,375,600

nCr=n!r!(nr)!

(3) 24C4=24!4!20!=24×23×22×214×3×2×1=10,626

(4) 19C14=19!14!5!=19×18×17×16×155×4×3×2×1=11,628

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