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Question

Find the value of r if cofficient of (2r+2)th and (r+1)th terms in the expansion of (1+x)43 are equal.

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Solution

If coefficient of (2r+2)th term and (r+1)th term in (1+x)43 are equal
Tr+1=43Cr(x)r
T2r+2=43C2r+1(x)2r+1
Now 43Cr=43C2r+1
So r=2r+1 or r+2r+1=43
r=1 not possible
So 3r+1=43

r=14


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