Question

Find the value of $se{c}^{2}x$ - $cose{c}^{2}x$.

• A. 1
• B. +
• C. -
• D. -

Answer 1

The correct option is D

-

When we look at the options, they are in terms of tanx and cotx. So will try to express $se{c}^{2}x$ and $cose{c}^{2}x$ in terms of

We know $se{c}^{2}x$ = 1 + $ta{n}^{2}x$ and

$cose{c}^{2}x$ = 1 + $co{t}^{2}x$

$\Rightarrow$ $se{c}^{2}x$ - $cose{c}^{2}x$ = $ta{n}^{2}x$ - $co{t}^{2}x$