Question

Find the value of $\sec {510}^{\circ }$

Answer 1

Given, $\sec {510}^{\circ }$

$=\sec (5\times {90}^{\circ }+{60}^{\circ })$

Here $n=5$ is odd, so $\sec$ changes to $\csc$.

$=cosec\left({60}^{\circ }\right)$ since ${510}^{\circ }$ lies in second quadrant.

$=\frac{2}{\sqrt{3}}$