Find the value of series of combination of resistance R and X in Ω
A
14 Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
26 Ω
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8413Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 26 Ω For potentiometer the voltage source is providing constant current in the circuit and if R and X are connected in series it will form Wheatstone's network so the balancing condition is
XR=7060
X=7×126=14Ω
equivalent resistance of R and X in series=R+X=26ohms.Hence, correct answer is option B.