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Question

Find the value of : sin1[x1xx1x2]

A
sin1xsin11x
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B
sin1x+sin11x
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C
sin1xsin1x
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D
sin1x+sin1x
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Solution

The correct option is C sin1xsin1x
We know that: sin1x±sin1y=sin1[x1y2±y1x2]
Comparing with the above equation,
sin1[x1x2x1x2]
=sin1(x)sin1(x)

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