Question

Find the value of $sin\left({15}^{\circ }\right)$

Answer 1

$\sin {15}^0=\sin \left({45}^0-{30}^0\right)$

$\sin {15}^0=\sin {45}^0\cos {30}^0-\cos {45}^0\sin {30}^0$

$\sin {15}^0=\frac{\sqrt{3}-1}{2\sqrt{2}}$