find the value of (sin^2 135 +sec^2 135)^2

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{s i n}^{2} 40^{0} - {c o s}^{2} 50^{0}

(i) (s i n^{2} A c o s^{2} B - c o s^{2} A s i n^{2} B) = (s i n^{2} A - s i n^{2} B)

(i i) (t a n^{2} A s e c^{2} B - s e c^{2} A t a n^{2} B) = (t a n^{2} A - t a n^{2} B)

(i) s e c^{2} θ + c o s e c^{2} θ = s e c^{2} θ c o s e c^{2} θ

(i i) t a n^{2} θ - s i n^{2} θ = t a n^{2} θ s i n^{2} θ

(i i i) t a n^{2} θ + c o t^{2} θ + 2 = s e c^{2} θ c o s e c^{2} θ

{sin}^{2} \frac{π}{10} + {sin}^{2} \frac{4 π}{10} + {sin}^{2} \frac{6 π}{10} + {sin}^{2} \frac{9 π}{10}

\frac{{s i n}^{2} 70^{o}}{{c o s}^{2} 20^{o}} + \frac{{c s c}^{2} 20^{o}}{{s e c}^{2} 70^{o}} - 2 c o s 70^{o} c o s e c 20^{o}

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