Question

Find the value of ${\sin }^2{30}^{\circ }+{\cos }^2{60}^{\circ }$

Answer 1

Solution:

${\sin }^2{30}^{\circ }+{\cos }^2{60}^{\circ }={\left(\frac{1}{2}\right)}^2+{\left(\frac{1}{2}\right)}^2$ where $(\sin {30}^{\circ }=\frac{1}{2},\cos {60}^{\circ }=\frac{1}{2})$

$=\frac{1}{4}+\frac{1}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$