Find the value of ${s i n}^{2} 40^{0} - {c o s}^{2} 50^{0}$

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Solution

${sin}^{2} 40^{\circ} - {cos}^{2} 50^{\circ}$
$= {sin}^{2} 40^{\circ} - {cos}^{2} (90^{\circ} - 40^{\circ})$
$= {sin}^{2} 40^{\circ} - {sin}^{2} 40^{\circ} = 0$

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