Find the value of sin270∘.
Find the value given trigonometric expression.
Given, sin270∘can be expressed as, sin270∘=sin(180∘+90∘)
Since sin is a periodic function of time period 2π, also negative in third quadrant or sin(π+θ)=−sinθ,whereπ=180∘
Therefore,
sin270∘=sin(180∘+90∘)=-sin90∘=-1∴sin270∘=-1Hence, the value of sin270∘is-1.