Find the value of sin $48^{o}$ sec $42^{o}$ + cos $48^{o}$ cosec $42^{o}$ .

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Solution

sin $48^{o}$ sec $42^{o}$ + cos $48^{o}$ cosec $42^{o}$

$= s i n 48 \times s e c (90 - 48) + c o s 48 \times c o s e c (90 - 48)$

$= s i n 48 \times c o s e c 48 + c o s 48 \times s e c 48$

$= s i n 48 \times (\frac{1}{s i n 48}) + c o s 48 \times (\frac{1}{c o s 48})$

$= 1 + 1 = 2 = R H S$

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Similar questions

sin 48^{\circ} sec 42^{\circ} + cos 48^{\circ} cosec 42^{\circ} = 2

Prove that:

(i) tan $20^{o} t a n 35^{o} t a n 45^{o} t a n 55^{o} t a n 70^{o} = 1$

(ii) sin $48^{o} s e c 42^{o} + c o s 48^{o} c o s e c 42^{o} = 2$

(iii) $\frac{s i n 70^{o}}{c o s 20^{o}} + \frac{c o s e c 20^{o}}{s e c 70^{o}} - 2 c o s 70^{o} c o s e c 20^{o} = 0$

(iv) $\frac{c o s 80^{o}}{s i n 10^{o}} + c o s 59^{o} c o s e c 31^{o} = 2$

Sin48.sec42+cos48.cosec42= ........

sin 48^{\circ} sin 12^{\circ}

\frac{\sqrt{3}}{\sqrt{2}}

cos 48^{\circ} cos 12^{\circ}

\frac{\sqrt{15} + \sqrt{3}}{4}

sin 75^{\circ} + sin 15^{\circ}

\frac{\sqrt{5} - 1}{8}

sin 24^{\circ} + cos 6^{\circ}

\frac{3 + \sqrt{5}}{8}

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