Question

Find the value of $sin(60°+\theta )-cos(30°-\theta ).$

• A. $2cos\theta$
• B. $2sin\theta$
• C. $0$
• D. $1$

Answer 1

The correct option is C

$0$

To find the value of :

$sin({60}^{\circ }+\theta )-cos({30}^{\circ }-\theta )=cos({90}^{\circ }-({60}^{\circ }+\theta \left)\right)-cos({30}^{\circ }-\theta )(\because cos({90}^{\circ }-\theta )=sin\theta )=cos({30}^{\circ }-\theta )-cos({30}^{\circ }-\theta )=0$