Question

Find the value of $\sin (-\frac{11\pi }{3})$

Answer 1

$\sin \left(\frac{-11\pi }{3}\right)$

$=-\sin \left(\frac{11\pi }{3}\right)$

$=-\sin (2\pi +\frac{5\pi }{3})$

$=-\sin \left(\frac{5\pi }{3}\right)$

$=-\sin (\pi +\frac{2\pi }{3})$

$=-(-\sin (\pi +\frac{2\pi }{3}))$

$=\sin \left(\frac{2\pi }{3}\right)$

$=\sin (\pi -\frac{\pi }{3})$

$=\sin \frac{\pi }{3}$

$=\frac{\sqrt{3}}{2}$