Find the value of sin θglass below:
Given nair = 1 nglass = 1.5
1/√3
nair sinθair = nwater sinθwater and nwater sinθwater = nglass sinθglass
Hence, nair sinθair = nglass sinθglass
⇒ sinθglass = nairnglass, sinθair = 11.5 sin 60∘ = √32 × (1.5) = 1√3