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Question

# Find the value of √10+√25+√108+√154+√225+(√225729−√25144)÷√1681

A
6916
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B
547
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C
313
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D
10813
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Solution

## The correct option is A 6916Given that √10+√25+√108+√154+√225+(√225729−√25144)÷√1681 we can find root step by step √10+√25+√108+√154+√225+(√225729−√25144)÷√1681 =√10+√25+√108+√154+15+(√225729−512)÷49 =√10+√25+√108+√169+(√2581−512)÷49 =√10+√25+√108+13+(59−512)÷49 =√10+√25+√121+536÷49 =√10+√25+11+54×14 =√10+√36+516 =√10+6+516 =√16+516 =4+516 =64+516 =6916 This is the required solution.

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