Find the value of -12-12-12-

The correct option is C 4Lets √(12+√(12+√(12+...)))= y Then y = √(12+y) Squaring on both sides y^2 = 12 + y ⇒ nbsp; y^2 y 12 = 0 Solving the quadratic ...

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Quantitative Aptitude

Quadratic Equations

Find the valu...

Question

Find the value of $\sqrt{12 + \sqrt{12 + \sqrt{12 + . . . .}}}$

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Solution

The correct option is C 4
Lets $\sqrt{12 + \sqrt{12 + \sqrt{12 + . . .}}} = y$

Then y = $\sqrt{12 + y}$

Squaring on both sides y $^{2}$ = 12 + y $\Rightarrow$
y $^{2}$ - y - 12 = 0

Solving the quadratic equation, we get y = 4 or -3

The sum cannot be negative, hence y = 4

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Similar questions

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P = \sqrt{(\sqrt{12}) + 12 + \sqrt{(13 + 2 \sqrt{12}))}} - \sqrt{12}

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Q. Find the value of:
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[12 + (- 4)] + . . . . . . = 12 + [. . . . + 3]

Q. If

(x + 1)^{2} - (x - 1)^{2} = 32

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Find the value of √12+√12+√12+....

The correct option is C 4Lets √12+√12+√12+...=y Then y = √12+y Squaring on both sides y2 = 12 + y ⇒ y2 - y - 12 = 0 Solving the quadratic equation, we get y = 4 or -3 The sum cannot be negative, hence y = 4

Find the value of $\sqrt{12 + \sqrt{12 + \sqrt{12 + . . . .}}}$

The correct option is C 4
Lets $\sqrt{12 + \sqrt{12 + \sqrt{12 + . . .}}} = y$

Then y = $\sqrt{12 + y}$

Squaring on both sides y $^{2}$ = 12 + y $\Rightarrow$
y $^{2}$ - y - 12 = 0

Solving the quadratic equation, we get y = 4 or -3

The sum cannot be negative, hence y = 4