Question

Find the value of $\sqrt[3]{3729}+\sqrt{729}$

Answer 1

Let $a=\sqrt[3]{3729}+\sqrt{729}$

$=\sqrt[3]{39\times 9\times 9}+\sqrt{27\times 27}$

$a=9+27=36$

$\therefore \sqrt[3]{3729}+\sqrt{729}=36$