Question

Find the value of $\sqrt[3]{3\sqrt[3]{3\frac{0.027}{0.008}}-\sqrt{\frac{0.09}{0.04}}}-1$

• A. 1
• B. -1
• C. 0.0
• D. $\frac{3}{2}$

Answer 1

The correct option is B -1

$\sqrt[3]{3\sqrt[3]{3\frac{0.027}{0.008}}-\sqrt{\frac{0.09}{0.04}}}-1$
$=\sqrt[3]{3\sqrt[3]{3(\frac{0.3}{0.2}{)}^3}-\sqrt{(\frac{0.3}{0.2}{)}^2}}-1$
$=\sqrt[3]{3\frac{0.3}{0.2}-\frac{\mathrm{0..3}}{0.2}}-1$
$=\sqrt[3]{30}-1$
$=-1$