Find the value of -484-121

The correct option is C 2 √(484121) = 2211 = 2 ...

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Question

Find the value of $\sqrt{\frac{484}{121}}$

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⎡ ⎢ ⎣ \begin{matrix} 413 \end{matrix} ⎤ ⎥ ⎦ A = ⎡ ⎢ ⎣ \begin{matrix} - 4 & 8 & 4 - 1 & 2 & 1 - 3 & 6 & 3 \end{matrix} ⎤ ⎥ ⎦

A

A = [a, b, c]

a + b + c

\sqrt{\frac{289}{484}}

⎡ ⎢ ⎣ \begin{matrix} 413 \end{matrix} ⎤ ⎥ ⎦ A = ⎡ ⎢ ⎣ \begin{matrix} - 4 & 8 & 4 - 1 & 2 & 1 - 3 & 6 & 3 \end{matrix} ⎤ ⎥ ⎦,

A = [\begin{matrix} a & b & c \end{matrix}] .

a + b + c .

The value of $\sqrt{484}$ is equal to

[\begin{matrix} 1 & 1 \\ 0 & 1 \end{matrix}] A = [\begin{matrix} 3 & 3 & 5 \\ 1 & 0 & 1 \end{matrix}]

A [\begin{matrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{matrix}] = [\begin{matrix} - 7 & - 8 & - 9 \\ 2 & 4 & 6 \end{matrix}]

[\begin{matrix} 4 \\ 1 \\ 3 \end{matrix}] A = [\begin{matrix} - 4 & 8 & 4 \\ - 1 & 2 & 1 \\ - 3 & 6 & 3 \end{matrix}]

[\begin{matrix} 2 & 1 & 3 \end{matrix}] [\begin{matrix} - 1 & 0 & - 1 \\ - 1 & 1 & 0 \\ 0 & 1 & 1 \end{matrix}] [\begin{matrix} 1 \\ 0 \\ - 1 \end{matrix}] = A

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