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Question

FInd the value of 7k=0 (cos2kπ7+isin2kπ7)


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Solution

We know,Sum of the n roots of unity = 0

6k=0 (cos2kπ7+isin2kπ7) = 0

7k=0 cos2kπ7+isin2kπ7 = 6k=0 (cos2kπ7+isin2kπ7) + cos2π +isin2π

= 0 + 1 = 1


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