Find the value of t if $p (1) = 3$ , given that $p (x) = x^{3} + 3 x^{2} + 2 x + t$ .

-3

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-2

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Solution

The correct option is A -3
Since, it is given that $p (1) = 3$
Given: $p (x) = x^{3} + 3 x^{2} + 2 x + t$ .

On substituting the value of x = 1 in the given polynomial,
$\Rightarrow$ $p (1) = 1^{3} + 3 \times 1^{2} + 2 \times 1 + t$
$\Rightarrow$ $3 = 1 + 3 + 2 + t$
$\Rightarrow$ $t = - 3$

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