Find the value of t which satisfies the following equation.
$6 (t - 2) + 7 (3 - 8 t) = 4 (t - 2) - 4 (4 - t)$

\frac{- 11}{8}

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\frac{11}{8}

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\frac{4}{3}

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\frac{33}{58}

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Solution

The correct option is D $\frac{33}{58}$
The given equation,
$6 (t - 2) + 7 (3 - 8 t) = 4 (t - 2) - 4 (4 - t)$
$\Rightarrow 6 t - 12 + 21 - 56 t = 4 t - 8 - 16 + 4 t$
$\Rightarrow 6 t + 9 - 56 t = 4 t - 24 + 4 t$
$\Rightarrow - 50 t + 9 = 8 t - 24$
$\Rightarrow - 50 t - 8 t = - 24 - 9$
$\Rightarrow - 58 t = - 33$
$\Rightarrow t = \frac{- 33}{- 58}$
$\Rightarrow t = \frac{33}{58}$

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