Find the value of:
${tan}^{2} 30^{o} + {tan}^{2} 45^{o}$

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Solution

${tan}^{2} 30^{\circ} + {tan}^{2} 45^{\circ}$
$= {(\frac{1}{\sqrt{3}})}^{2} + {(1)}^{2}$
$= \frac{1}{3} + 1$
$= \frac{1 + 3}{3} = \frac{4}{3}$

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