Find the value of $tan 2 A$ , if $cos 3 A = 45^{o}$ .

Open in App

Solution

It is given that, $cos 3 A = sin 45$ , then,

$cos 3 A = cos (90 - 45)$

$3 A = 45$

$A = 15$

$2 A = 30$

$tan 2 A = tan 30$

$tan 2 A = \frac{1}{\sqrt{3}}$

Suggest Corrections

Similar questions

sin A + sin 3A/ cos A + cos 3A = tan 2A

\frac{sin A + 2 sin 2 A + sin 3 A}{cos A + 2 cos 2 A + cos 3 A} = tan 2 A

Find the value of $\frac{c o s^{3} A - c o s 3 A}{c o s A}$ + $\frac{s i n^{3} A - s i n 3 A}{s i n A}$

tan A - \frac{1}{tan A} = \sqrt{2}

{tan}^{2} A + \frac{1}{{tan}^{2} A}

{cot}^{2} A - 3 = 0

cos 3 A

Join BYJU'S Learning Program