Question

find the value of Tan 49/Cot 41

Answer 1

$$\begin{gathered} \frac{\tan 49°}{\cot 41°} \\ =\frac{\tan 49°}{\cot \left(90°-49°\right)} \\ =\frac{\tan 49°}{\tan 49°}\left[\mathrm{as},\cot \left(90°-\mathrm{\theta }\right)=\tan \mathrm{\theta }\right] \\ =1 \end{gathered}$$