Question

Find the value of $\tan {75}^o$.

Answer 1

Now,

$\tan {75}^o$

$=\tan ({30}^o+{45}^o)$

$=\frac{\tan {30}^o+\tan {45}^o}{1-\tan {30}^o.\tan {45}^o}$

$=\frac{\frac{1}{\sqrt{3}}+1}{1-\frac{1}{\sqrt{3}}}$

$=\frac{\sqrt{3}+1}{\sqrt{3}-1}$.