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Byju's Answer
Standard XII
Mathematics
Sin(A+B)Sin(A-B)
Find the valu...
Question
Find the value of
tan
[
sin
−
1
(
1
√
2
)
+
cos
(
sin
−
1
(
1
2
)
+
tan
−
1
(
√
3
)
)
]
−
cos
e
c
(
tan
−
1
4
3
)
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Solution
⇒
tan
[
sin
−
1
(
1
√
2
)
+
(
sin
−
1
1
2
)
+
tan
−
1
√
3
]
−
cos
e
c
(
tan
−
1
4
3
)
=
tan
[
tan
−
1
(
1
1
)
+
(
tan
−
1
1
√
3
)
+
tan
−
1
√
3
]
−
cos
e
c
(
cos
e
c
−
1
5
4
)
=
tan
[
π
+
π
6
+
π
3
]
−
cos
e
c
(
cos
e
c
−
1
5
4
)
=
tan
[
3
π
4
]
−
cos
e
c
(
cos
e
c
−
1
5
4
)
=
−
1
−
5
4
=
−
9
4
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0
Similar questions
Q.
Find the value of
t
a
n
−
1
(
−
1
√
3
)
+
c
o
t
−
1
(
1
√
3
)
+
t
a
n
−
1
[
s
i
n
(
−
π
2
)
]
.
Q.
Evaluate:
(a)
sin
−
1
4
5
+
2
tan
−
1
1
3
=
π
2
(b)
tan
−
1
1
7
+
2
tan
−
1
1
3
=
π
4
(c)
tan
−
1
1
5
+
tan
−
1
1
7
+
tan
−
1
1
3
+
tan
−
1
1
8
=
π
4
Q.
Inverse circular functions,Principal values of
s
i
n
−
1
x
,
c
o
s
−
1
x
,
t
a
n
−
1
x
.
t
a
n
−
1
x
+
t
a
n
−
1
y
=
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
<
1
π
+
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
>
1
.
(a) Given
0
≤
x
≤
1
2
then the value of
t
a
n
[
s
i
n
−
1
{
x
√
2
+
√
1
−
x
2
√
2
}
−
s
i
n
−
1
x
]
is
(b) If
α
=
s
i
n
−
1
4
5
+
s
i
n
−
1
1
3
and
β
=
c
o
s
−
1
4
5
+
c
o
s
−
1
1
3
,
Q.
Consider the following :
1.
sin
−
1
4
5
+
sin
−
1
3
5
=
π
2
2.
tan
−
1
√
3
+
tan
−
1
1
=
−
tan
−
1
(
2
+
√
3
)
Which of the above is/are correct?
Q.
Show that
t
a
n
−
1
1
2
+
t
a
n
−
1
2
11
+
t
a
n
−
1
4
3
=
π
2
.
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